AGS.Editor.GUIController.ShowViewChooserFromPropertyGrid C# (CSharp) Метод

ShowViewChooserFromPropertyGrid() приватный Метод

private ShowViewChooserFromPropertyGrid ( int currentView ) : int
currentView int
Результат int
        private int ShowViewChooserFromPropertyGrid(int currentView)
        {
            AGS.Types.View chosenView = ViewChooser.ShowViewChooser(null, currentView);
            if (chosenView == null)
            {
                return currentView;
            }
            return chosenView.ID;
        }
GUIController