ATML1671Translator.model.numbers.Deserialize C# (CSharp) Метод

Deserialize() публичный статический Метод

public static Deserialize ( string input ) : numbers
input string
Результат numbers
        public static numbers Deserialize(string input)
        {
            StringReader stringReader = null;
            try
            {
                stringReader = new StringReader(input);
                return ((numbers)(Serializer.Deserialize(System.Xml.XmlReader.Create(stringReader))));
            }
            finally
            {
                if ((stringReader != null))
                {
                    stringReader.Dispose();
                }
            }
        }

Same methods

numbers::Deserialize ( string input, numbers &obj ) : bool
numbers::Deserialize ( string input, numbers &obj, Exception &exception ) : bool
numbers::Deserialize ( Stream s ) : numbers