ATML1671Translator.model.numbers.Deserialize C# (CSharp) Метод

public static Deserialize ( Stream s ) : numbers
s	Stream
Результат	numbers

        public static numbers Deserialize(Stream s)
        {
            return ((numbers)(Serializer.Deserialize(s)));
        }
        #endregion

Same methods

numbers::Deserialize ( string input, numbers &obj ) : bool
numbers::Deserialize ( string input, numbers &obj, Exception &exception ) : bool
numbers::Deserialize ( string input ) : numbers

numbers