ATML1671Translator.model.numbers.Deserialize C# (CSharp) Метод

Deserialize() публичный статический Метод

Deserializes workflow markup into an numbers object
public static Deserialize ( string input, numbers &obj, Exception &exception ) : bool
input string string workflow markup to deserialize
obj numbers Output numbers object
exception System.Exception output Exception value if deserialize failed
Результат bool
        public static bool Deserialize(string input, out numbers obj, out Exception exception)
        {
            exception = null;
            obj = default(numbers);
            try
            {
                obj = Deserialize(input);
                return true;
            }
            catch (Exception ex)
            {
                exception = ex;
                return false;
            }
        }

Same methods

numbers::Deserialize ( string input, numbers &obj ) : bool
numbers::Deserialize ( Stream s ) : numbers
numbers::Deserialize ( string input ) : numbers