public void WithUserType()
{
tableName = ObjectName.Parse("APP.test");
var columns = new[] {
new SqlTableColumn("id", PrimitiveTypes.Integer()),
new SqlTableColumn("t", AdminQuery.Context.ResolveType("APP.test_type")),
};
AdminQuery.CreateTable(tableName, columns);
Assert.IsTrue(AdminQuery.Access().TableExists(tableName));
}