Deveel.Data.CreateTableTests.WithUserType C# (CSharp) Method

        public void WithUserType()
        {
            tableName = ObjectName.Parse("APP.test");
            var columns = new[] {
                new SqlTableColumn("id", PrimitiveTypes.Integer()),
                new SqlTableColumn("t", AdminQuery.Context.ResolveType("APP.test_type")),
            };

            AdminQuery.CreateTable(tableName, columns);

            Assert.IsTrue(AdminQuery.Access().TableExists(tableName));
        }