Box2D.Common.Mat33.Solve33 C# (CSharp) Метод

Solve A * x = b, where b is a column vector. This is more efficient than computing the inverse in one-shot cases.

        public Vec3 Solve33(Vec3 b)
        {
            Vec3 x = new Vec3();
            Solve33ToOut(b, x);
            return x;
        }

Mat33