BamlLocalization.ResourceGenerator.GetOutputFileName C# (CSharp) Метод

        private static string GetOutputFileName(LocBamlOptions options)
        {
            string outputFileName;
            string inputFileName  = Path.GetFileName(options.Input);

            switch(options.InputType)
            {
                case FileType.BAML:
                {
                    return inputFileName;
                }
            case FileType.EXE:
            {
                     inputFileName = inputFileName.Remove(inputFileName.LastIndexOf('.')) + ".resources.dll";
            return inputFileName;
            }
                case FileType.DLL :
                {
                    return inputFileName;
                }
                case FileType.RESOURCES :
                {
                    // get the output file name
                    outputFileName        = inputFileName;

                    // get to the last dot seperating filename and extension
                    int lastDot = outputFileName.LastIndexOf('.');
                    int secondLastDot = outputFileName.LastIndexOf('.', lastDot - 1);
                    if (secondLastDot > 0)
                    {
                        string cultureName = outputFileName.Substring(secondLastDot + 1, lastDot - secondLastDot - 1);
                        if (LocBamlConst.IsValidCultureName(cultureName))
                        {
                            string extension = outputFileName.Substring(lastDot);
                            string frontPart = outputFileName.Substring(0, secondLastDot + 1);
                            outputFileName = frontPart + options.CultureInfo.Name + extension;
                        }
                    }
                    return outputFileName;
                }
                default :
                {
                    throw new NotSupportedException();
                }
            }
        }