AspNet.FileUploadHandler.WriteJsonResponse C# (CSharp) Метод

        private void WriteJsonResponse(HttpContext context, List<FileDescriptor> results)
        {
            context.Response.ContentType = "application/json";

            JsonResponse response = new JsonResponse() { Success = true, Response = new Dictionary<string, object>() };
            response.Response.Add("files", results.ToArray());

            var jsonObj = JsonConvert.SerializeObject(response);
            context.Response.Write(jsonObj);
        }