AspNet.FileUploadHandler.UploadFile C# (CSharp) Метод

        private void UploadFile(HttpContext context)
        {
            var results = new List<FileDescriptor>();

            int chunk = (string.IsNullOrWhiteSpace(context.Request["chunk"]) ? -1 : Convert.ToInt32(context.Request["chunk"]));
            int totalChunks = (string.IsNullOrWhiteSpace(context.Request["totalChunks"]) ? 0 : Convert.ToInt32(context.Request["totalChunks"]));
            string uid = context.Request["uid"];
            string filename = context.Request["filename"];

            if (chunk == -1)
                results.AddRange(UploadWholeFile(context, uid, filename));
            else
                results.Add(UploadPartialFile(context, uid, filename, chunk, totalChunks));

            WriteJsonResponse(context, results);
        }