AdventureWorks.Controllers.DepartmentsController.Details C# (CSharp) Метод

        public ActionResult Details(short? id)
        {
            if (id == null)
            {
                return new HttpStatusCodeResult(HttpStatusCode.BadRequest);
            }
            Department department = db.Departments.Find(id);
            if (department == null)
            {
                return HttpNotFound();
            }
            return View(department);
        }