AdventureWorks.Controllers.DepartmentsController.DepartmentsController C# (CSharp) Метод

DepartmentsController() публичный Метод

public DepartmentsController ( AdventureWorks.Models.AdventureWorksContext context ) : System
context AdventureWorks.Models.AdventureWorksContext
Результат System
        public DepartmentsController(AdventureWorksContext context)
        {
            db = context;
        }