ATMLModelLibrary.model.test.Outcome.Deserialize C# (CSharp) Метод

Deserialize() публичный статический Метод

Deserializes workflow markup into an Outcome object
public static Deserialize ( string input, Outcome &obj, System &exception ) : bool
input string string workflow markup to deserialize
obj Outcome Output Outcome object
exception System output Exception value if deserialize failed
Результат bool
        public static bool Deserialize(string input, out Outcome obj, out System.Exception exception)
        {
            exception = null;
            obj = default(Outcome);
            try
            {
                obj = Deserialize(input);
                return true;
            }
            catch (System.Exception ex)
            {
                exception = ex;
                return false;
            }
        }

Same methods

Outcome::Deserialize ( System s ) : Outcome
Outcome::Deserialize ( string input ) : Outcome
Outcome::Deserialize ( string input, Outcome &obj ) : bool