ATMLModelLibrary.model.test.Outcome.Deserialize C# (CSharp) Метод

        public static Outcome Deserialize(string input)
        {
            System.IO.StringReader stringReader = null;
            try
            {
                stringReader = new System.IO.StringReader(input);
                return ((Outcome)(Serializer.Deserialize(System.Xml.XmlReader.Create(stringReader))));
            }
            finally
            {
                if ((stringReader != null))
                {
                    stringReader.Dispose();
                }
            }
        }