ATMLModelLibrary.model.signal.basic.DigitalBus.Deserialize C# (CSharp) Метод

Deserialize() публичный статический Метод

Deserializes workflow markup into an DigitalBus object
public static Deserialize ( string input, DigitalBus &obj, System &exception ) : bool
input string string workflow markup to deserialize
obj DigitalBus Output DigitalBus object
exception System output Exception value if deserialize failed
Результат bool
        public static bool Deserialize(string input, out DigitalBus obj, out System.Exception exception)
        {
            exception = null;
            obj = default(DigitalBus);
            try
            {
                obj = Deserialize(input);
                return true;
            }
            catch (System.Exception ex)
            {
                exception = ex;
                return false;
            }
        }

Same methods

DigitalBus::Deserialize ( System s ) : DigitalBus
DigitalBus::Deserialize ( string input ) : DigitalBus
DigitalBus::Deserialize ( string input, DigitalBus &obj ) : bool