ATMLModelLibrary.model.signal.basic.DigitalBus.Deserialize C# (CSharp) Метод

Deserialize() публичный статический Метод

public static Deserialize ( string input ) : DigitalBus
input string
Результат DigitalBus
        public new static DigitalBus Deserialize(string input)
        {
            System.IO.StringReader stringReader = null;
            try
            {
                stringReader = new System.IO.StringReader(input);
                return ((DigitalBus)(Serializer.Deserialize(System.Xml.XmlReader.Create(stringReader))));
            }
            finally
            {
                if ((stringReader != null))
                {
                    stringReader.Dispose();
                }
            }
        }

Same methods

DigitalBus::Deserialize ( System s ) : DigitalBus
DigitalBus::Deserialize ( string input, DigitalBus &obj ) : bool
DigitalBus::Deserialize ( string input, DigitalBus &obj, System &exception ) : bool