ATMLModelLibrary.model.equipment.Resource.Deserialize C# (CSharp) Method

        public new static Resource Deserialize(string input)
        {
            StringReader stringReader = null;
            try
            {
                stringReader = new StringReader(input);
                return ((Resource)(Serializer.Deserialize(System.Xml.XmlReader.Create(stringReader))));
            }
            finally
            {
                if ((stringReader != null))
                {
                    stringReader.Dispose();
                }
            }
        }