ATMLModelLibrary.model.equipment.Resource.Deserialize C# (CSharp) Method

Deserialize() public static method

public static Deserialize ( Stream s ) : Resource
s Stream
return Resource
        public static Resource Deserialize(Stream s)
        {
            return ((Resource)(Serializer.Deserialize(s)));
        }
        #endregion

Same methods

Resource::Deserialize ( string input ) : Resource
Resource::Deserialize ( string input, Resource &obj ) : bool
Resource::Deserialize ( string input, Resource &obj, Exception &exception ) : bool