TvDatabase.TvBusinessLayer.GetCardByName C# (CSharp) Method

    public Card GetCardByName(string name)
    {
      IList<Card> cards = Cards;
      foreach (Card card in cards)
      {
        if (card.Name == name)
        {
          return card;
        }
      }
      return null;
    }

    static void Main(string[] args)
    {
      TvBusinessLayer layer = new TvBusinessLayer();
      layer.AddCard("name1", "path1", 1);
      layer.AddCard("name2", "path2", 2);
      layer.AddCard("name3", "path3", 3);
      layer.AddCard("name4", "path4", 4);

      Card card = layer.GetCardByName("name2");
      card = layer.GetCardByDevicePath("path4");

      Channel channel = layer.AddChannel("provider", "name");
      channel = layer.AddChannel("provider", "name");
      

      DatabaseManager.Instance.SaveChanges();

    }