System.Runtime.Serialization.Json.XmlJsonWriter.ThrowInvalidAttributeContent C# (CSharp) Method

        private void ThrowInvalidAttributeContent()
        {
            if (HasOpenAttribute)
            {
                throw new XmlException(SR.JsonInvalidMethodBetweenStartEndAttribute);
            }
            else
            {
                throw new XmlException(SR.Format(SR.JsonCannotWriteTextAfterNonTextAttribute, _dataType.ToString().ToLowerInvariant()));
            }
        }