System.CodeDom.Compiler.CodeCompiler.FromFile C# (CSharp) Method

FromFile() private method

private FromFile ( CompilerParameters options, string fileName ) : CompilerResults
options CompilerParameters
fileName string
return CompilerResults
        protected virtual CompilerResults FromFile(CompilerParameters options, string fileName) {
            if( options == null) {
                throw new ArgumentNullException("options");
            }
            if (fileName == null)
                throw new ArgumentNullException("fileName");

            new SecurityPermission(SecurityPermissionFlag.UnmanagedCode).Demand();
            
            // Try opening the file to make sure it exists.  This will throw an exception
            // if it doesn't
            using (Stream str = File.OpenRead(fileName)) { }

            string[] filenames = new string[1];
            filenames[0] = fileName;
            return FromFileBatch(options, filenames);
        }