Dev2.Models.ExplorerItemModel.Debug C# (CSharp) Method

        private void Debug()
        {
            var environmentModel = EnvironmentRepository.Instance.FindSingle(model => model.ID == EnvironmentId);
            if(environmentModel != null)
            {
                var resourceModel = environmentModel.ResourceRepository.FindSingle(model => model.ID == ResourceId);
                if(resourceModel != null)
                {
                    Edit();
                    EventPublishers.Aggregator.Publish(new DebugResourceMessage(resourceModel as IContextualResourceModel));
                }
            }
        }