System.Xml.Schema.XmlSchemaException.GetObjectData C# (CSharp) Метод

		public override void GetObjectData(SerializationInfo info, StreamingContext context) {
            base.GetObjectData(info, context);
            info.AddValue("res",                res);
            info.AddValue("args",               args);
            info.AddValue("sourceUri",          sourceUri);
            info.AddValue("lineNumber",         lineNumber);
            info.AddValue("linePosition",       linePosition);
            info.AddValue("version",            "2.0");
        }

		public void PermitOnlySerializationFormatter_GetObjectData ()
		{
			StreamingContext sc = new StreamingContext (StreamingContextStates.All);
			XmlSchemaException xe = new XmlSchemaException (String.Empty, null);
			xe.GetObjectData (null, sc);
		}