System.ServiceModel.Http2Protocol.Http2Stream.SendRST C# (CSharp) Метод

Sends the RST to the stream.

public SendRST ( StatusCode reason ) : void
reason	StatusCode	The reason.
Результат	void

        public void SendRST(StatusCode reason)
        {
            this.protocol.SendRST(this, reason);
        }

Http2Stream