System.Linq.Tests.SumTests.SumOfDecimal_SourceIsNull_ArgumentNullExceptionThrown C# (CSharp) Метод

        public void SumOfDecimal_SourceIsNull_ArgumentNullExceptionThrown()
        {
            IQueryable<decimal> sourceDecimal = null;
            Assert.Throws<ArgumentNullException>("source", () => sourceDecimal.Sum());
            Assert.Throws<ArgumentNullException>("source", () => sourceDecimal.Sum(x => x));
        }