SenseNet.ContentRepository.Storage.Schema.SchemaRoot.PermissionTypeToXml C# (CSharp) Метод

		private static void PermissionTypeToXml(PermissionType permType, StringBuilder sb, string indent)
		{
            sb.Append(indent).AppendLine(String.Format(CultureInfo.CurrentCulture, "<PermissionType itemID=\"{0}\" name=\"{1}\" />", permType.Id, permType.Name));
		}