PackageExplorerViewModel.PackageViewModel.GetCurrentPackageStream C# (CSharp) Метод

        public Stream GetCurrentPackageStream()
        {
            string tempFile = Path.GetTempFileName();
            PackageHelper.SavePackage(PackageMetadata, GetFiles(), tempFile, false);
            if (File.Exists(tempFile)) {
                return File.OpenRead(tempFile);
            }
            else {
                return null;
            }
        }