Meyn.TestLink.TestLink.GetTestCase C# (CSharp) Метод

GetTestCase() публичный Метод

get a test case by its id
public GetTestCase ( int testcaseid, int versionId ) : TestCase
testcaseid int Id of the test case
versionId int (optional) the version id. If not given the latest version is returned
Результат TestCase
        public TestCase GetTestCase(int testcaseid, int versionId = 0)
        {
            stateIsValid();
            object o = null;
            if (versionId == 0)
                o = proxy.getTestCase(devkey, testcaseid);
            else
                o = proxy.getTestCase(devkey, testcaseid, versionId);
            handleErrorMessage(o);
            XmlRpcStruct[] rList = o as XmlRpcStruct[];
            return new TestCase(rList[0]);
        }