Gurpenator.GurpsCharacter.toJson C# (CSharp) Метод

        public object toJson()
        {
            return new Dictionary<string, object> {
                { "name", Name } ,
                { "layout", layout.toJson() },
                { "purchases", new List<object>(from purchase in getAllPurchases()
                                                select new Dictionary<string, object> {
                                                    {"trait", purchase.property.name},
                                                    {"purchased", purchase.PurchasedLevels},
                                                })
                },
            };
        }