Deveel.Data.Sql.Statements.SqlTableColumn.IStatementPreparable C# (CSharp) Метод

        object IStatementPreparable.Prepare(IRequest context)
        {
            var columnType = ColumnType.Resolve(context);
            return new SqlTableColumn(ColumnName, columnType) {
                IsIdentity = IsIdentity,
                IsNotNull = IsNotNull,
                IndexType = IndexType,
                DefaultExpression = DefaultExpression
            };
        }