Deveel.Data.Sql.Statements.CreateTableStringFormatTests.WithIdentityColumn C# (CSharp) Метод

        public static void WithIdentityColumn()
        {
            var statement = new CreateTableStatement(new ObjectName("test_table"),
                new[] {
                    new SqlTableColumn("id", PrimitiveTypes.Integer()) {
                        IsIdentity = true
                    },
                    new SqlTableColumn("name", PrimitiveTypes.String()),
                });

            var sql = statement.ToString();

            var expected = new StringBuilder();
            expected.AppendLine("CREATE TABLE test_table (");
            expected.AppendLine("  id INTEGER IDENTITY,");
            expected.AppendLine("  name STRING");
            expected.Append(")");

            Assert.AreEqual(expected.ToString(), sql);
        }