Data.EDM.BlockSerializer.DeserializeBlockFromXML C# (CSharp) Метод

        public Block DeserializeBlockFromXML(String filePath)
        {
            FileStream fileStream = new FileStream(filePath, FileMode.Open);
            Block block = null;
            block = (Block)xmls.Deserialize(fileStream);
            fileStream.Close();
            return block;
        }