BatchGuy.App.Shared.Services.DisplayErrorMessageService.DisplayError C# (CSharp) Метод

        public void DisplayError(ErrorMessage errorMessage)
        {
            _loggingService.LogErrorFormat(errorMessage.Exception, errorMessage.MethodNameWhereExceptionOccurred);
            MessageBox.Show(string.Format("{0}.  Please view the error log for more details.",errorMessage.DisplayMessage), errorMessage.DisplayTitle, MessageBoxButtons.OK, MessageBoxIcon.Error);
        }