Application.Web.Controllers.LaptopsAdministrationController.Details C# (CSharp) Метод

        public ActionResult Details(int? id)
        {
            if (id == null)
            {
                return new HttpStatusCodeResult(HttpStatusCode.BadRequest);
            }
            Laptop laptop = db.Laptops.Find(id);
            if (laptop == null)
            {
                return HttpNotFound();
            }
            return View(laptop);
        }