AjaxControlToolkit.PersistentStoreManager.GetFileName C# (CSharp) Метод

        public string GetFileName(string controlId)
        {
            if(String.IsNullOrEmpty(controlId))
                throw new ArgumentException("controlId cannot be empty", "controlId");

            var currentContext = GetCurrentContext();
            if(currentContext == null)
                return String.Empty;

            var postedFile = currentContext.Session[GetFullID(controlId)] as HttpPostedFile;
            if(postedFile == null)
                return String.Empty;

            return postedFile.FileName;
        }