ATMLModelLibrary.model.uut.SoftwareUUTStatusCode.Deserialize C# (CSharp) Метод

Deserialize() публичный статический Метод

public static Deserialize ( string input, SoftwareUUTStatusCode &obj ) : bool
input string
obj SoftwareUUTStatusCode
Результат bool
        public static bool Deserialize(string input, out SoftwareUUTStatusCode obj)
        {
            System.Exception exception;
            return Deserialize(input, out obj, out exception);
        }

Same methods

SoftwareUUTStatusCode::Deserialize ( System s ) : SoftwareUUTStatusCode
SoftwareUUTStatusCode::Deserialize ( string input ) : SoftwareUUTStatusCode
SoftwareUUTStatusCode::Deserialize ( string input, SoftwareUUTStatusCode &obj, System &exception ) : bool