ATMLModelLibrary.model.test.Action.Deserialize C# (CSharp) Метод

Deserialize() публичный статический Метод

public static Deserialize ( System s ) : Action
s System
Результат Action
        public static Action Deserialize(System.IO.Stream s)
        {
            return ((Action)(Serializer.Deserialize(s)));
        }
        #endregion

Same methods

Action::Deserialize ( string input ) : Action
Action::Deserialize ( string input, Action &obj ) : bool
Action::Deserialize ( string input, Action &obj, System &exception ) : bool