ATMLModelLibrary.model.signal.basic.Step.Deserialize C# (CSharp) Метод

Deserialize() публичный статический Метод

public static Deserialize ( System s ) : Step
s System
Результат Step
        public static Step Deserialize(System.IO.Stream s)
        {
            return ((Step)(Serializer.Deserialize(s)));
        }
        #endregion

Same methods

Step::Deserialize ( string input ) : Step
Step::Deserialize ( string input, Step &obj ) : bool
Step::Deserialize ( string input, Step &obj, System &exception ) : bool