ATMLModelLibrary.model.signal.basic.Sensor.Deserialize C# (CSharp) Метод

Deserialize() публичный статический Метод

public static Deserialize ( string input, Sensor &obj ) : bool
input string
obj Sensor
Результат bool
        public static bool Deserialize(string input, out Sensor obj)
        {
            System.Exception exception;
            return Deserialize(input, out obj, out exception);
        }

Same methods

Sensor::Deserialize ( System s ) : Sensor
Sensor::Deserialize ( string input ) : Sensor
Sensor::Deserialize ( string input, Sensor &obj, System &exception ) : bool