ATMLModelLibrary.model.equipment.Resources.Deserialize C# (CSharp) Метод

Deserialize() публичный статический Метод

Deserializes workflow markup into an Resources object
public static Deserialize ( string input, Resources &obj, Exception &exception ) : bool
input string string workflow markup to deserialize
obj Resources Output Resources object
exception System.Exception output Exception value if deserialize failed
Результат bool
        public static bool Deserialize(string input, out Resources obj, out Exception exception)
        {
            exception = null;
            obj = default(Resources);
            try
            {
                obj = Deserialize(input);
                return true;
            }
            catch (Exception ex)
            {
                exception = ex;
                return false;
            }
        }

Same methods

Resources::Deserialize ( Stream s ) : Resources
Resources::Deserialize ( string input ) : Resources
Resources::Deserialize ( string input, Resources &obj ) : bool