ATMLModelLibrary.model.equipment.Path.Deserialize C# (CSharp) Метод

Deserialize() публичный статический Метод

public static Deserialize ( System s ) : Path
s System
Результат Path
        public static Path Deserialize(System.IO.Stream s)
        {
            return ((Path)(Serializer.Deserialize(s)));
        }
        #endregion

Same methods

Path::Deserialize ( string input ) : Path
Path::Deserialize ( string input, Path &obj ) : bool
Path::Deserialize ( string input, Path &obj, System &exception ) : bool