ATMLModelLibrary.model.equipment.IEEE488.Deserialize C# (CSharp) Метод

public static Deserialize ( Stream s ) : IEEE488
s	Stream
Результат	IEEE488

        public static IEEE488 Deserialize(Stream s)
        {
            return ((IEEE488)(Serializer.Deserialize(s)));
        }
        #endregion

Same methods

IEEE488::Deserialize ( string input ) : IEEE488
IEEE488::Deserialize ( string input, IEEE488 &obj ) : bool
IEEE488::Deserialize ( string input, IEEE488 &obj, Exception &exception ) : bool

IEEE488