ATMLModelLibrary.model.common.UserDefinedIdentificationNumber.Deserialize C# (CSharp) Метод

Deserialize() публичный статический Метод

Deserializes workflow markup into an UserDefinedIdentificationNumber object
public static Deserialize ( string input, UserDefinedIdentificationNumber &obj, System &exception ) : bool
input string string workflow markup to deserialize
obj UserDefinedIdentificationNumber Output UserDefinedIdentificationNumber object
exception System output Exception value if deserialize failed
Результат bool
        public static bool Deserialize(string input, out UserDefinedIdentificationNumber obj, out System.Exception exception)
        {
            exception = null;
            obj = default(UserDefinedIdentificationNumber);
            try
            {
                obj = Deserialize(input);
                return true;
            }
            catch (System.Exception ex)
            {
                exception = ex;
                return false;
            }
        }

Same methods

UserDefinedIdentificationNumber::Deserialize ( System s ) : UserDefinedIdentificationNumber
UserDefinedIdentificationNumber::Deserialize ( string input ) : UserDefinedIdentificationNumber
UserDefinedIdentificationNumber::Deserialize ( string input, UserDefinedIdentificationNumber &obj ) : bool