API_3.Controllers.FigureController.GetRedirectResult C# (CSharp) Метод

        public RedirectResult GetRedirectResult()
        {
            UrlHelper helper = new UrlHelper(Request);
            IDictionary<string, object> route = new Dictionary<string, object>();
            route["controller"] = "Figure";
            route["action"] = "GetAll";

            return new RedirectResult(new Uri(helper.Link("DefaultApi", route)), this);
        }