AIMA.Core.Util.Math.Matrix.transpose C# (CSharp) Метод

	public Matrix transpose() {
		Matrix X = new Matrix(n, m);
		double[][] C = X.getArray();
		for (int i = 0; i < m; i++) {
			for (int j = 0; j < n; j++) {
				C[j][i] = A[i][j];
			}
		}
		return X;
	}

	/**
	 * Solve X*A = B, which is also A'*X' = B'
	 * 
	 * @param B
	 *            right hand side
	 * @return solution if A is square, least squares solution otherwise.
	 */

	public Matrix solveTranspose(Matrix B) {
		return transpose().solve(B.transpose());
	}