AGS.Types.SerializeUtils.GetElementString C# (CSharp) Метод

        public static string GetElementString(XmlNode node, string elementName)
        {
            XmlNode foundNode = node.SelectSingleNode(elementName);
            if (foundNode == null)
            {
                throw new InvalidDataException("Missing XML element: " + elementName);
            }
            return foundNode.InnerText;
        }

 public View(XmlNode node)
 {
     ID   = Convert.ToInt32(SerializeUtils.GetElementString(node, "ID"));
     Name = SerializeUtils.GetElementString(node, "Name");
     foreach (XmlNode loopNode in SerializeUtils.GetChildNodes(node, "Loops"))
     {
         _loops.Add(new ViewLoop(loopNode));
     }
 }