Template.Debug C# (CSharp) Метод

    public void Debug()
    {
        if (existingLogger.Level >= LogLevel.Debug)
        {
            existingLogger.Debug("df");
        }
    }
}

        private void btnViewDebug_Click(object sender, EventArgs e)
        {
            selectTemplateUserControl1.SaveSetting();

            this._table.Database.Selects = new List <Model.Table>()
            {
                _table
            };

            Template template = new Template();

            template.TemplateFolder = selectTemplateUserControl1.TemplateFolderPath;
            template.Database       = this._table.Database;
            template.Settings       = selectTemplateUserControl1.Settings;

            template.Debug();
            if (ShowDebug != null)
            {
                ShowDebug(template.DatabaseJson, template.SettingJson, true);
            }
        }