System.Xml.Xsl.Xslt.QilGenerator.ThrowErrorHelper.ReportError C# (CSharp) Method

            public void ReportError(string res, params string[] args) {
                Debug.Assert(args == null || args.Length == 0, "Error message must already be composed in res");
                throw new XslLoadException(Res.Xml_UserException, res);
            }