private static void ShowOutputWindowFrame(IServiceProvider serviceProvider)
{
Debug.Assert(serviceProvider != null, "Supplied service provider should not be null");
// Calling "Activate" on its own isn't enough if the Output window isn't already being shown
// we need to explicitly call "Show" on the window.
IVsUIShell shell = serviceProvider.GetService(typeof(SVsUIShell)) as IVsUIShell;
if (shell != null)
{
IVsWindowFrame windowFrame;
int hr = shell.FindToolWindow(0, VSConstants.StandardToolWindows.Output, out windowFrame);
Debug.Assert(ErrorHandler.Succeeded(hr), "Call to IVsUIShell FindTooWindow failed.");
if (ErrorHandler.Succeeded(hr) && windowFrame != null)
{
windowFrame.Show();
}
}
}
#endregion
