HttpServer.Server.OnRequest C# (CSharp) Method

        private void OnRequest(object sender, RequestEventArgs e)
        {
            _server = this;

            Exception exception;
            try
            {
                ProcessingResult result = HandleRequest(e);
                if (result != ProcessingResult.Continue)
                    return;

                exception = null;
            }
            catch (HttpException err)
            {
                _logger.Error("Got an HTTP exception.", err);
                e.Response.Status = err.Code;
                e.Response.Reason = err.Message;
                exception = err;
            }
            catch (Exception err)
            {
                _logger.Error("Got an unhandled exception.", err);
                exception = err;
                e.Response.Status = HttpStatusCode.InternalServerError;
                e.Response.Reason = "Failed to process request.";
            }


            if (exception == null)
            {
                e.Response.Status = HttpStatusCode.NotFound;
                e.Response.Reason = "Requested resource is not found. Sorry ;(";
                exception = new HttpException(HttpStatusCode.NotFound, "Failed to find uri " + e.Request.Uri);
            }
            DisplayErrorPage(e.Context, exception);
            e.IsHandled = true;
        }